could someone explain attached problem?
Thank you
ST
a1
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each term after the first is equal to twice the previous term
this simply means that a5 = 2*a4, a4 = 2*a3 and so on...
a5 - a2 = 12
2*(a4) - 2*(a1) = 12
2*2*(a3) - 2*(a1) = 12
4*2*(a2) - 2*(a1) = 12
8*2*(a1) - 2*(a1) = 12
16*(a1) - 2*(a1) = 12
14*(a1) = 12
a1 = 12/14 = 6/7
choose E.
-BM-
this simply means that a5 = 2*a4, a4 = 2*a3 and so on...
a5 - a2 = 12
2*(a4) - 2*(a1) = 12
2*2*(a3) - 2*(a1) = 12
4*2*(a2) - 2*(a1) = 12
8*2*(a1) - 2*(a1) = 12
16*(a1) - 2*(a1) = 12
14*(a1) = 12
a1 = 12/14 = 6/7
choose E.
-BM-