BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

A woman driving her car reaches her destination in 30 hours. If she reduces her speed

Expert replies
by Mikrislac » Fri Jul 31, 2020 4:00 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

A woman driving her car reaches her destination in 30 hours. If she reduces her speed by 1/15, then she travels 10 km less in the same amount of time. What is the original speed of the car in km/hr?

A. 4.0

B. 5.0

C. 5.5

D. 6.0

E. 7.5
Join the discussion
Source: — Problem Solving |

While travelling with speed S, the car covers distance in 30 hours
So total distance covered: 30*S
Reduced speed = 14s/15. and the distance covered in 30 hours = 30*S-10

on solving Speed*time= distance, we get s=5
OA:5km/hr
Join the discussion