1)
He sold a car for 20,000 with a profit of 25%
so 1.25 x = 20,000
x (purchase price) = 16,000 and profit = 20,000- 16,000 = 4000
2nd car sold for 20,000 with a loss of 20%
so 0.8 x = 20000
x = 25000 and loss = 25000 - 20000 = 5000 loss
Total profit/loss = 4000 profit - 5000 loss = 1000 loss
Answer is C
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A used-car dealer sold one car at ...
Source: Beat The GMAT — Problem Solving |
3)
rate of 6 machines = 1/12
rate of 1 machine = 1/12/6= 1/72
to find out how many machines we need to do the same job in 8 days
1/72 * no. of machines * 8 = 1
no. of machines = 72/8 = 9
so extra machines = 9 -6 = 3 machines
Answer is B
This is an article explaining various ways to solve the same problem: https://www.beatthegmat.com/six-machines ... 52992.html
rate of 6 machines = 1/12
rate of 1 machine = 1/12/6= 1/72
to find out how many machines we need to do the same job in 8 days
1/72 * no. of machines * 8 = 1
no. of machines = 72/8 = 9
so extra machines = 9 -6 = 3 machines
Answer is B
This is an article explaining various ways to solve the same problem: https://www.beatthegmat.com/six-machines ... 52992.html
Is there another way to solve this problem because I assume when we use " ! " we really need a calculator ? Thank you.MBA.Aspirant wrote:2)
18 applicants choose 4
18!/4! 14! = 3060
Answer is E
ssiva wrote:The formula is (n!)/[(n-r)! * r!] for a combination problem
18!/[(14!)(4!)] = (18*17*16*15)/(1*2*3*4) = 3060
