My answer would be E, 9, simply because 9 is the greatest of digits. If the first digit of the initial number is 9, then the second will be from 2 to 8 (0 is eliminated, since you have to flip the digits and obtain an odd number):
92 vs. 29
94 vs. 49
96 vs. 69
98 vs. 89
As you can see, all the numbers on the left are greater than the numbers on the right.
A counter example for why 3, for instance, cannot be the first digit of the required number would be 36. Flip the digits and you get an odd number, 63, that is greater than the original number.

Ah ok ok so just fill those digit in a ten digit numer like:

21
23
25
27
29

I misunderstand the question:$

Pick an original even number starting with each of the answer choices and only when the first digit of the original even number is 9 will the reversed number not be odd number greater than the original number.

Since 9 is highest single digit place value possible the even number's 2nd digit will always be less than 9.

If this is flipped the resulting number will always be smaller.

Hence E

consider 8 in the units place. for all the first four choices, reversal of digits makes the new no greater whereas for 9, it is the opposite.

89<98.

Consider this...

No is 10x+y , where x and y are 1st and second digit.

Resverse no. 10y+x should be less that original no. so

10x+y < 10y+x
x-y<0

so we need to find out 2 digis for which x-y>=0, for this relation 9-anyDigit will work.##Answer E.