A rectangular table seats 4 people on each of two sides, with every person directly facing another person across the table. If eight people choose their seats at random, what is the probability that any two of them directly face each other?
A) 1/56
B) 1/8
C) 1/7
D) 15/56
E) 4/7
OA is C
suppose their are 8 people A,B,C,D,E,F,G,H....so question is asking that what is the probability that A and B directly facing each other. if A selected a seat then B can select 1 seat from 7 options. so the right answer is [spoiler]1/7[/spoiler] however, i google this question and found that most of the explanation says its 4/7
A) 1/56
B) 1/8
C) 1/7
D) 15/56
E) 4/7
OA is C
suppose their are 8 people A,B,C,D,E,F,G,H....so question is asking that what is the probability that A and B directly facing each other. if A selected a seat then B can select 1 seat from 7 options. so the right answer is [spoiler]1/7[/spoiler] however, i google this question and found that most of the explanation says its 4/7
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