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A triangle \(ABC\) has area \(32\) sq units and its side \(BC,\) of length \(8\) units, lies on the line \(x = 4.\) Then the shortest possible distance between \(A\) and the point \((0,0)\) is
A. \(2\)
B. \(2\sqrt{2}\)
C. \(4\)
D. \(4\sqrt{2}\)
E. \(6\)
The OA is C
A. \(2\)
B. \(2\sqrt{2}\)
C. \(4\)
D. \(4\sqrt{2}\)
E. \(6\)
The OA is C
