BTGmoderatorDC wrote: ↑

Mon Nov 02, 2020 6:05 pm

A taxi charges d dollars for the first two miles and c cents per quarter mile for every mile after the first two. Which equation describes cost of a taxi ride of n miles in dollars.

A) dn – c/8(100)

B) cd + 4n-8/200

C) d + (4cn-8c)/100

D) d + 100cn/4

E) 4cd(n-2) – 100


OA C

Source: Veritas Prep

We have to calculate for n miles.
For first 2 miles , its \(d\$\)
For remaining \((n-2)\) miles , we calculate as:

\(1\) quarter mile \(= c\) cents
Therefore \(1\) mile \(= 4c\) cents

Also \(100 c = 1 d\)
Hence \(1\) mile cost \(= \dfrac{4c}{100} \$\)
For \(n-2\) miles cost \(= \dfrac{4c(n-2)}{100} = \dfrac{4cn - 8c}{100} \$\)

Total cost of n miles in \(\$ = d+ \dfrac{4cn - 8c}{100}\)

Therefore, C