BTGmoderatorLU wrote:Source: GMAT Prep

A straight line in the xy-plane has a slope of 2 and a y-intercept of 2. On this line, what is the x-coordinate of the point whose y-coordinate is 500?

A. 249
B. 498
C. 676
D. 823
E. 1,002

The OA is A

The question conveniently gives us the information to write the equation of the line in slope y-intercept form, y = mx + b, where m = slope and b = the y-intercept.

Line in the xy-plane has a slope of 2 and a y-intercept of 2
So, the equation of the line is: y = 2x + 2

On this line, what is the x-coordinate of the point whose y-coordinate is 500?
To find the corresponding x-value, we'll take the equation y = 2x + 2 and replace y with 500
We get: 500 = 2x + 2
To solve for x, first subtract 2 from both sides to get: 498 = 2x
Solve: x = 498/2 = 249

Answer: A

Cheers,
Brent