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A square garden is surrounded by a path of uniform width. If the path and the garden...

Expert replies
by BTGmoderatorLU » Fri Jun 19, 2020 4:43 am

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E

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Source: Magoosh

A square garden is surrounded by a path of uniform width. If the path and the garden both have an area of x, then what is the width of the path in terms of x?

A. \(x^2\)
B. \(2\sqrt{x}-\sqrt{2}\)
C. \(\dfrac{\sqrt{2}}{2}-\dfrac{x}{4}\)
D. \(\sqrt{2}-\dfrac{x}{2}\)
E. \(\dfrac{\sqrt{2x}}{2}-\dfrac{x}{2}\)

The OA is E
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Source: — Problem Solving |

Area of square garden = x
$$area\ =\ l^2$$
$$\sqrt{l^{^2}}=\sqrt{x}$$
$$l=\sqrt{x}=>\ length\ of\ each\ side\ =\sqrt{x}$$

Garden is surrounded by a path of uniform width, so the shape of the garden and the path will also form a square when combined.

Let the width of path = n
The length of the combined path and garden = length of garden + width of the path on right side + width of the path on the left side
$$combined\ length=\sqrt{x}+n+n$$
$$=\sqrt{x}+2n$$
$$area\ of\ path\ =x$$
$$area\ of\ garden=x$$
$$combined\ area\ =\left(combined\ length\right)^2=x+x\left[\sin ce\ combined\ shape\ is\ a\ square\right]$$
$$\left(combined\ length\right)^2=2x$$
$$where\ combined\ length\ =\ \sqrt{x}+2n$$
$$\sqrt{\left(x+2n\right)^2}=\sqrt{2x}$$
$$\sqrt{x+2n}=\sqrt{2x}$$
$$\frac{2n}{2}=\frac{\sqrt{2x}-\sqrt{x}}{2}$$
$$n=\frac{\sqrt{2x}-\sqrt{x}}{2}$$
$$\frac{\sqrt{2x}}{2}-\frac{\sqrt{x}}{2}$$
$$Answer\ =\ E$$
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