A right circular cylinder with a radius of 2 feet and a leng

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BTGmoderatorDC: Moderator; Posts: 7187; Joined: Thu Sep 07, 2017 4:43 pmFollowed by: 23 members

by BTGmoderatorDC » Wed Mar 06, 2019 8:48 pm

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A right circular cylinder with a radius of 2 feet and a length of 6 feet is cut into three equal pieces. What is the volume, in cubic feet, of each of the three pieces?

A. 2Ï€
B. 3Ï€
C. 8Ï€
D. 12Ï€
E. 24Ï€

OA C

Source: Princeton Review

Source: Beat The GMAT — Problem Solving | Wed Mar 06, 2019 8:48 pm

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Jay@ManhattanReview: GMAT Instructor; Posts: 3008; Joined: Mon Aug 22, 2016 6:19 amFollowed by: 34 members; Location: Grand Central / New York; Thanked: 470 times

by Jay@ManhattanReview » Wed Mar 06, 2019 9:49 pm

BTGmoderatorDC wrote:

A right circular cylinder with a radius of 2 feet and a length of 6 feet is cut into three equal pieces. What is the volume, in cubic feet, of each of the three pieces?

A. 2Ï€
B. 3Ï€
C. 8Ï€
D. 12Ï€
E. 24Ï€

OA C

Source: Princeton Review

Given that the height of the cylinder is 6, the height of each of the three pieces = 6/3 = 2 feet

Thus, the volume of each of the three pieces = Ï€r^2*h = Ï€*2^2*2 = 8Ï€ feet^3

The correct answer: C

Hope this helps!

-Jay
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by Scott@TargetTestPrep » Thu Mar 14, 2019 5:59 am

BTGmoderatorDC wrote:

A right circular cylinder with a radius of 2 feet and a length of 6 feet is cut into three equal pieces. What is the volume, in cubic feet, of each of the three pieces?

A. 2π
B. 3π
C. 8π
D. 12π
E. 24π

OA C

Source: Princeton Review

The formula for the volume of a right circular cylinder is V = π x r^2 x h; thus, the volume of the entire cylinder is:

π x 2^2 x 6 = 24π ft^3

So when it’s cut into 3 equal pieces, the volume of each piece is 24π/3 = 8π ft^3.

Answer: C

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