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A recent lunch meeting at a certain club was attended by members and guests. Each member paid $4 for the lunch and

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by BTGmoderatorDC » Sun Oct 11, 2020 5:35 pm

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B

C

D

E

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A recent lunch meeting at a certain club was attended by members and guests. Each member paid $4 for the lunch and each guest paid $8 for the lunch. How many of the people attending the meeting were members


(1) A total of 20 people attended the meeting.

(2) A total of $92 was paid for the lunch


OA C

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Re: A recent lunch meeting at a certain club was attended by members and guests. Each member paid $4 for the lunch and

by jhavyom » Mon Oct 12, 2020 10:41 am
A recent lunch meeting at a certain club was attended by members and guests. Each member paid $4 for the lunch and each guest paid $8 for the lunch. How many of the people attending the meeting were members


(1) A total of 20 people attended the meeting.

Members and guests can be 10 each
Members can be 5 in number and the guests can be 15 in number.
Insufficient.

(2) A total of $92 was paid for the lunch

1 member and 11 guests can be present.
Or, 3 members and 10 guests can be present.
Insufficient.

Combining (1) and (2)
We get two equations with two variables
Let members = M and guests = G

M + G = 20 ...(i)
4M + 8G = 92 ...(ii)

Thus, we get unique value of M and G
Sufficient
C is the answer
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