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Start the plan(A) 9
(B) 15
(C) 21
(D) 35
(E) 56
[spoiler]OA=D[/spoiler]
Source: Magoosh
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Start the planThe no. of different three-day combinations of the seven weekdays that can be constructed = 7C3 = (7.6.5)/(1.2.3) = 35Vincen wrote: ↑Thu May 07, 2020 11:35 amA radio station has to choose three days of the seven in a week to broadcast a certain program, and that set will repeat each week. The program can be broadcast equally on any of the seven weekdays — weekdays vs. weekends don’t matter at all — nor does it matter whether the days the program airs are adjacent or not. Absolutely any three of the seven weekdays can be chosen. How many different three-day combinations of the seven weekdays can be constructed?
(A) 9
(B) 15
(C) 21
(D) 35
(E) 56
[spoiler]OA=D[/spoiler]
Source: Magoosh
The number of different three-day combinations of the seven weekdays can be constructed is:Vincen wrote: ↑Thu May 07, 2020 11:35 amA radio station has to choose three days of the seven in a week to broadcast a certain program, and that set will repeat each week. The program can be broadcast equally on any of the seven weekdays — weekdays vs. weekends don’t matter at all — nor does it matter whether the days the program airs are adjacent or not. Absolutely any three of the seven weekdays can be chosen. How many different three-day combinations of the seven weekdays can be constructed?
(A) 9
(B) 15
(C) 21
(D) 35
(E) 56
[spoiler]OA=D[/spoiler]
Source: Magoosh
