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A poll reveals that the average (arithmetic mean) income of \(10\) households is \(\$25,000.\) If \(6\) of the household

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by M7MBA » Wed Oct 07, 2020 10:07 am
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A poll reveals that the average (arithmetic mean) income of \(10\) households is \(\$25,000.\) If \(6\) of the households have incomes of \(\$30,000\) each, what is the average income of the other \(4\) households?

A. \(\$21,500\)
B. \(\$20,500\)
C. \(\$17,500\)
D. \(\$7,500\)
E. \(\$7,000\)

Answer: C

Source: Official Guide
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Re: A poll reveals that the average (arithmetic mean) income of \(10\) households is \(\$25,000.\) If \(6\) of the house

by Scott@TargetTestPrep » Thu Oct 22, 2020 9:30 am
M7MBA wrote: ↑
Wed Oct 07, 2020 10:07 am
 A poll reveals that the average (arithmetic mean) income of \(10\) households is \(\$25,000.\) If \(6\) of the households have incomes of \(\$30,000\) each, what is the average income of the other \(4\) households?

A. \(\$21,500\)
B. \(\$20,500\)
C. \(\$17,500\)
D. \(\$7,500\)
E. \(\$7,000\)

Answer: C

Source: Official Guide
Solution:

The overall sum of the 10 households is 10 x 25,000 = 250,000.

The sum of 6 of the households is 6 x 30,000 = 180,000. Thus, we know that the sum of the incomes of the remaining 4 households is 250,000- 180,000 = 70,000.

Thus, the average of those other 4 households is 70,000/4 = 17,500.

Answer: C

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