A photo is going to be taken of 8 people arranged in two rows. Three people will be in the first row and 5 people will

Total no of ways of arranging 8 people $$=8!$$
There is only one way to arrange sabah that is in is in the leftmost position in first row
George is somewhere in the backrow and there are 5 places there, so
number of ways to arrange George
$$=5C_1=\frac{5!}{1!\left(5-1\right)!}=\frac{5!}{1\cdot4!}=5$$
Removing George and Sabah, Total number of people left = (8-2)=6 and they can be arranged in 6! ways in which Sabah can be placed in the leftmost position and also with George somewhere in the back row $$=5\cdot6!$$ $$\Pr obabaility=\frac{5\cdot6!}{8!}$$ $$Answer\ is\ Option\ B$$