BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

A parking garage has spaces for cars and vans only. If there is a total of 118 vehicles in the garage, how many of them

Expert replies
by BTGmoderatorDC » Sun Oct 31, 2021 6:27 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

A parking garage has spaces for cars and vans only. If there is a total of 118 vehicles in the garage, how many of them are vans?

(1) If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage.

(2) If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.


OA A

Source: Princeton Review
Join the discussion
Source: — Data Sufficiency |

BTGmoderatorDC wrote:
Sun Oct 31, 2021 6:27 pm
A parking garage has spaces for cars and vans only. If there is a total of 118 vehicles in the garage, how many of them are vans?

(1) If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage.

(2) If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.


OA A

Source: Princeton Review
Given: A parking garage has spaces for cars and vans only. There is a total of 118 vehicles in the garage,
Let C = the number of cars
Let V = the number of vans
We can write: C + V = 118

Target question: What is the value of V?

Statement 1: If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage
We can write: V + 14 = 2C

We now have the following system of two different linear equations:
V + 14 = 2C
C + V = 118
Since we COULD solve the system for C and for V, we could answer the target question (although we would never waste valuable time on test day doing so)
Statement 1 is NOT SUFFICIENT

Statement 2: If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.
We can write: V + x = C + y
There are several values of x, y, V and C that satisfy statement 2 (and the given information, C + V = 118). Here are two possible cases:
Case a: V = 59, C = 59, x = 3 and y = 3. In this case, the answer to the target question is V = 59
Case b: V = 58, C = 60, x = 3 and y = 1. In this case, the answer to the target question is V = 58
Since we can’t answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer: A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion