Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

A palindrome, such as 12321, is a number that remains the sa

Expert replies
by Max@Math Revolution » Mon Jul 01, 2019 12:23 am
Timer
00:00
Your answer
Difficulty–

right wrong

Pick an answer to see how members did

[GMAT math practice question]

A palindrome, such as 12321, is a number that remains the same when its digits are reversed. The numbers x and x+32 are three-digit and four-digit palindromes, respectively. What is the sum of the digits of x?

A. 18
B. 24
C. 28
D. 32
E. 36
Join the discussion
Source: — Problem Solving |

by GMATGuruNY » Mon Jul 01, 2019 1:49 am
Max@Math Revolution wrote:[GMAT math practice question]

A palindrome, such as 12321, is a number that remains the same when its digits are reversed. The numbers x and x+32 are three-digit and four-digit palindromes, respectively. What is the sum of the digits of x?

A. 18
B. 24
C. 28
D. 32
E. 36
The difference between the two palindromes = 32.
Since subtracting 32 from the 4-digit palindrome must yield a 3-digit palindrome. the 4-digit palindrome must be just a bit more than 1000.
Test 1001:
1001 - 32 = 969
Success!
Subtracting 32 from 1001 (a 4-digit palindrome) yields 969 (a 3-digit palindrome).
Since x=969, the sum of its digits = 9+6+9 = 24.

The correct answer is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by Max@Math Revolution » Tue Jul 02, 2019 11:42 pm
=>

Let x = ABA and x + 32 = CDDC.
Then CDDC = ABA + 32
Since CDDC has a thousands digit, we must have A = 9.
Then the units digit of CDDC is equal to the units digit of A + 2 = 11.
And, looking at the tens digits, we must have B + 3 + 1 ≥ 10.
Therefore, B ≥ 6.
The possible values for B are:
B = 6, 7, 8, 9.
Let’s check which value gives a palindrome for ABA + 32:
969 + 32 = 1001
979 + 32 = 1011
989 + 32 = 1021
999 + 32 = 1031
The only palindrome is 1001, so x = 969.
Thus, the sum of the digits of x is 9 + 6 + 9 = 24.

Therefore, B is the answer.
Answer: B
Join the discussion