A math question: og Math Q122 ????

is the answer c?

It wants you to substitute the above operation to fit the question at hand. If

a*b=(a-b)/(a+b), then
a*c=(a-c)/(a+c).

We know that "a" is not equal to "-b", which means that "a" and "b" are the same number, but "b" is the negation of a. So if a=5, then b cannot be -5. This is because the equation above will become infinity when the denominator is 0. Therefore we can use this same rule to show that "a" does not equal "-c"

Back to our problem. If we know a*c=(a-c)/(a+c) and a*c = 0, then

(a-c)/(a+c)=0. Since we know that a+c is a non-zero value, that must mean that a-c=0, or a=c. Thus the answer would be E.

awesomeusername wrote:It wants you to substitute the above operation to fit the question at hand. If

a*b=(a-b)/(a+b), then
a*c=(a-c)/(a+c).

We know that "a" is not equal to "-b", which means that "a" and "b" are the same number, but "b" is the negation of a. So if a=5, then b cannot be -5. This is because the equation above will become infinity when the denominator is 0. Therefore we can use this same rule to show that "a" does not equal "-c"

Back to our problem. If we know a*c=(a-c)/(a+c) and a*c = 0, then

(a-c)/(a+c)=0. Since we know that a+c is a non-zero value, that must mean that a-c=0, or a=c. Thus the answer would be E.

Well! Suddenly, everything just starts to make sense to me. I thought too deep. It's just a wried question. Anywayz.. thanks for the explanation