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A lecture course consists of 595 students. The students

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by BTGModeratorVI » Wed Jul 29, 2020 2:43 pm

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Answers

A

B

C

D

E

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Difficulty—

A lecture course consists of 595 students. The students are to be divided into discussion sections, each with an equal number of students. Which of the following cannot be the number of students in a discussion section.

a) 17
b) 35
c) 45
d) 85
e) 119


Answer: C
Source: Veritas Prep
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Re: A lecture course consists of 595 students. The students

by Brent@GMATPrepNow » Sat Aug 01, 2020 6:24 am
BTGModeratorVI wrote: ↑
Wed Jul 29, 2020 2:43 pm
 A lecture course consists of 595 students. The students are to be divided into discussion sections, each with an equal number of students. Which of the following cannot be the number of students in a discussion section.

a) 17
b) 35
c) 45
d) 85
e) 119


Answer: C
Source: Veritas Prep
In order to have an EQUAL number of students in each section, the number of students per section MUST BE A FACTOR of 595

Let's do some prime factorization
595 = (5)(7)(17)
From the prime factorization, we can see that answer choice A, B, D and E are all factors of 595

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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Re: A lecture course consists of 595 students. The students

by Ignite » Sat Aug 01, 2020 11:37 pm
We are being asked to find that 595 is not divisible by which number among the given options.

595 = 5 * 7 * 17

17: Prime factor of 595
35: 5 * 7
85: 5 * 17
119: 7*17

45: Cannot be formed by the prime factors of 595.

Answer C


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Sayon
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