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A grocer stacked oranges in a pile. The bottom layer was rectangular with 3 rows of 5 oranges each. In the second layer

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by VJesus12 » Fri Jul 09, 2021 11:37 am
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A grocer stacked oranges in a pile. The bottom layer was rectangular with 3 rows of 5 oranges each. In the second layer from the bottom, each orange rested on 4 oranges from the bottom layer, and in the third layer, each orange rested on 4 oranges from the second layer. Which of the following is the maximum number of oranges that could have been in the third layer?

(A) 5
(B) 4
(C) 3
(D) 2
(E) 1

Answer: C

Source: GMAT Prep
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Source: — Problem Solving |

VJesus12 wrote: ↑
Fri Jul 09, 2021 11:37 am
A grocer stacked oranges in a pile. The bottom layer was rectangular with 3 rows of 5 oranges each. In the second layer from the bottom, each orange rested on 4 oranges from the bottom layer, and in the third layer, each orange rested on 4 oranges from the second layer. Which of the following is the maximum number of oranges that could have been in the third layer?

(A) 5
(B) 4
(C) 3
(D) 2
(E) 1

Answer: C

Source: GMAT Prep
So the second layer is a 2*4 matrix. There are three such possibilities in the third layer where the orange in the top layer will touch 4 oranges in the second layer.
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VJesus12 wrote: ↑
Fri Jul 09, 2021 11:37 am
A grocer stacked oranges in a pile. The bottom layer was rectangular with 3 rows of 5 oranges each. In the second layer from the bottom, each orange rested on 4 oranges from the bottom layer, and in the third layer, each orange rested on 4 oranges from the second layer. Which of the following is the maximum number of oranges that could have been in the third layer?

(A) 5
(B) 4
(C) 3
(D) 2
(E) 1

Answer: C

Source: GMAT Prep
Bottom Layer \(= 5 \times 3 = 15\)
2nd Layer \(= (5-1) \times (3-1) = 8\)
3rd Layer \(= (4-1) \times (2-1) = 3\)

Therefore, C
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