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by mehrasa » Sun Sep 25, 2011 11:54 pm
if a divided by b with remainder 5 and c divided by d with remainder 8. what is the smallest possible value for b+d?
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by shankar.ashwin » Mon Sep 26, 2011 12:08 am
6+9=15?
OA?
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by mehrasa » Mon Sep 26, 2011 12:13 am
shankar.ashwin wrote:6+9=15?
OA?
ya OA is also 15.. it was interesting, easy though :)
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by knight247 » Mon Sep 26, 2011 12:51 am
Hey Ashwin,
Can you explain how u arrived at the answer?
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by shankar.ashwin » Mon Sep 26, 2011 1:03 am
For the remainder to be 5, the denominator 'b' of the fraction (a/b) should be more than 5. (if it is 5, remainder will be 0)

So minimum value b could take is 6 (to possibly give a remainder of 5)

Similarly for the other fraction remainder is 8, so minimum value of Denominator should be 9.

They ask for minimum value b+d can take, so this is the minimum.
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