BTGmoderatorLU wrote:Source: Princeton Review

A focus group is currently made up of x men and y women. If 2 men and 4 women are added to the group, and if one person is selected at random from the larger focus group, then what is the probability that a man is selected?

A. x/(x + 2)
B. x/(x + y)
C. (x + 2)/(x + y + 2)
D. (y + 4)/(x + y + 6)
E. (x + 2)/(x + y + 6)

The OA is E

With the addition of 2 men and 4 women, there are (x + 2) men out of (x + y + 6) persons

Thus, the probability that a man is selected = (x + 2)/(x + y + 6)

The correct answer: E

Hope this helps!

-Jay
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BTGmoderatorLU wrote:Source: Princeton Review

A focus group is currently made up of x men and y women. If 2 men and 4 women are added to the group, and if one person is selected at random from the larger focus group, then what is the probability that a man is selected?

A. x/(x + 2)
B. x/(x + y)
C. (x + 2)/(x + y + 2)
D. (y + 4)/(x + y + 6)
E. (x + 2)/(x + y + 6)

The OA is E

After the addition of the new members, there are (x + 2) men and (y + 4) women in the group, and so the total number of individuals in the focus group is now (x + y + 6). Thus, the probability that a man is selected is (x + 2)/(x + y + 6).

Answer: E