a farm used 2 harvesting machines h and k

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a farm used 2 harvesting machines h and k

by andes1 » Mon Dec 17, 2007 7:29 pm
i had it correct but was a result of an educated guess... how to...

here is the question
Image
Last edited by andes1 on Tue Dec 18, 2007 4:59 pm, edited 1 time in total.
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by camitava » Mon Dec 17, 2007 8:31 pm
andes1, for the first Qs -
H can harvest 40 acres in 8 hrs.
So in 1hr it has harvested 5 acres.
Let K can harvest k acres/hr
So (5 + k) acres can be done by both the machines in 1 hr
(100 - 40) = 60 acres [H has already harvested 40 acres so 60 is left to harvest] should be in 60/(5 + k)
Therefore, 60/(5 + k) = 5
So k = 7
Ur second link is not working fine.
Correct me If I am wrong


Regards,

Amitava

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by andes1 » Tue Dec 18, 2007 4:58 pm
Thanks for your answer

Also I solved this point using my “educated guess” and maybe using my bizarre logic.

WE KNOW THAT AFTER 8 HOURS MACHINE H harvested 40 acres
8/40 after simplified 1/5 (5 acres x hour).

Now, we know that the total of acres is 100, then 100-40(harvested acres) = 60 acres remaining.

If the machine H harvest at the same rate, we will know that after 5 hours the total of acres harvested is 25… 1/25.
Next, 60 acres remaining- 25(acres harvested by machine h) = 35 acres which the machine k has to harvest in 5 hours…
So
35acres remaining / 5 hours = 7
Answer 7
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by camitava » Tue Dec 18, 2007 9:38 pm
Hey andes1, as u said -
Also I solved this point using my “educated guess” and maybe using my bizarre logic.
is alternative approach to solve this kind of problem. This u can not say as an educated guess but rather a good logic to solve this type of problem.
Correct me If I am wrong


Regards,

Amitava