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by diebeatsthegmat » Sun Jun 26, 2011 11:21 am
A certain city owns 298 buses, whose routes are divided into three zones. At a given time, if q buses are in the blue zone, r buses are in the red zone, s buses are in the green zone, and t buses are in garages, how many buses are in the green zone?

(1) The ratio of q to r to s is 4:6:7 and 26 buses are in garages.

(2) q = 64
my answer is A and its wrong.... how do you solve this?
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Source: — Data Sufficiency |
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by pemdas » Sun Jun 26, 2011 12:44 pm
from statement(1) t=26+Z and 17Y=(298-26-Z). Your mistake is that you assume t=26, BUT it doesn't say Only 26 buses are in garages or all buses that are in garages 26 Not Sufficient
statement(2) q=64 and (298-64)=234 buses are in red zone, green zone and in garages Not Sufficient
combined statements(1&2): 64/4=16 makes it clear for s=16*7 Sufficient

iom c
diebeatsthegmat wrote:A certain city owns 298 buses, whose routes are divided into three zones. At a given time, if q buses are in the blue zone, r buses are in the red zone, s buses are in the green zone, and t buses are in garages, how many buses are in the green zone?

(1) The ratio of q to r to s is 4:6:7 and 26 buses are in garages.

(2) q = 64
my answer is A and its wrong.... how do you solve this?
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