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A dance troupe has a total of 50 dancers split into 2 groups.

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by BTGModeratorVI » Thu May 07, 2020 5:55 am

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A dance troupe has a total of 50 dancers split into 2 groups. The costumes worn by Group A cost $80 each, and those worn by Group B cost $90 each. If the total cost of all the costumes is $4,270, what is the total cost of the costumes worn by Group B ?

(A) $1,840
(B) $2,070
(C) $2,135
(D) $2,160
(E) $2,430

Answer: E
Source: Official guide 2021
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Re: A dance troupe has a total of 50 dancers split into 2 groups.

by Scott@TargetTestPrep » Sun May 10, 2020 11:43 am
BTGModeratorVI wrote: ↑
Thu May 07, 2020 5:55 am
 A dance troupe has a total of 50 dancers split into 2 groups. The costumes worn by Group A cost $80 each, and those worn by Group B cost $90 each. If the total cost of all the costumes is $4,270, what is the total cost of the costumes worn by Group B ?

(A) $1,840
(B) $2,070
(C) $2,135
(D) $2,160
(E) $2,430

Answer: E
Source: Official guide 2021
We can create the equation:

A + B = 50

and

80A + 90B = 4270

Multiplying the first equation by 90, we have:

90A + 90B = 4500

Subtracting the second equation from this new equation, we have:

10A = 230

A = 23

Therefore, group B has 50 - 23 = 27 dancers. Since each of their costumes costs $90, the total cost of the costumes worn by Group B is 27 x 90 = $2430.

Answer: E

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