LUANDATO wrote:A dairy farmer has 3 different kinds of milk of quantities: 82 litres, 123 litres, and 205 litres respectively. Find the least number of casks of equal size required to store all the milk without mixing.
Note: The size of each cask should be an integer.
A)9
B)10
C)12
D)15
E) 8
Total volume of milk = 82 + 123 + 205 = (2*41 + 3*41 + 5*41) =
41(2 + 3 + 5) = 41*10.
The products in blue imply that the three distinct volumes -- 82,123, 205 -- can be stored without mixing in 10 41-liter casks, as follows:
82 liters --> 2 41-liter casks
123 liters --> 3 41-liter casks
205 liters --> 5 41-liter casks.
Thus, the smallest possible number of casks = 2+3+5 = 10.
The correct answer is
B.
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