Quant 2 Q 160
A couple decides to have 4 children. If they succeed in having 4 children and each child is equally likely to be a boy or a girl, what is the probablity that they will have exactly 2 girls and 2 boys?
A) 3/8
B) 1/4
C) 3/16
D) 1/8
E) 1/16
I understand the answer should be number of possibilities of 2 girls 2 boys, which is 4!/2!2!, divided by total possibilities. Rather than list these out, how can we use the combination formula to figure out total number of possibilities (simply, its 2x2x2x2, but i'm trying to figure out if a question is way more complex than this what is formula for total number of combinations possible)
A couple decides to have 4 children. If they succeed in having 4 children and each child is equally likely to be a boy or a girl, what is the probablity that they will have exactly 2 girls and 2 boys?
A) 3/8
B) 1/4
C) 3/16
D) 1/8
E) 1/16
I understand the answer should be number of possibilities of 2 girls 2 boys, which is 4!/2!2!, divided by total possibilities. Rather than list these out, how can we use the combination formula to figure out total number of possibilities (simply, its 2x2x2x2, but i'm trying to figure out if a question is way more complex than this what is formula for total number of combinations possible)
