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A computer store originally bought 1,000 modems

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by BTGModeratorVI » Fri Mar 06, 2020 5:56 pm
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A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

(A) d/800
(B) 5d/1000
(C) 125d
(D) d/1000 + 25
(E) 125/(1000d)

Answer: A
Source: Veritas Prep
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Re: A computer store originally bought 1,000 modems

by swerve » Sat Mar 07, 2020 6:08 am
BTGModeratorVI wrote: ↑
Fri Mar 06, 2020 5:56 pm
 A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

(A) d/800
(B) 5d/1000
(C) 125d
(D) d/1000 + 25
(E) 125/(1000d)

Answer: A
Source: Veritas Prep
\begin{array}{|c|c|c|}
\hline
\text{Quantity} & \text{Each Cost} & Total \\ \hline
1000 & \dfrac{d}{1000} & d \\ \hline
\end{array}

Adding \(25\% \) to \(\dfrac{d}{1000} \quad \Rightarrow \quad \dfrac{d}{1000}\cdot \dfrac{125}{100} = \dfrac{d}{800}.\)
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Re: A computer store originally bought 1,000 modems

by Brent@GMATPrepNow » Sat Mar 07, 2020 7:12 am
BTGModeratorVI wrote: ↑
Fri Mar 06, 2020 5:56 pm
 A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

(A) d/800
(B) 5d/1000
(C) 125d
(D) d/1000 + 25
(E) 125/(1000d)

Answer: A
Source: Veritas Prep
Given: d = total cost of 1000 modems
So, d/1000 = cost of ONE modem

After the 25% increase, the retail price per modem = (d/1000) + 25% of (d/1000)
= (d/1000) + 0.25 (d/1000)
= d/1000 + 0.25d/1000
= 1.25d/1000
Check answer choices . . . . not there!
We need to find an equivalent form of 1.25d/1000 that's among the answer choices.

Take: 1.25d/1000
Divide top and bottom by 1.25 to get: d/800

Answer: A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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Re: A computer store originally bought 1,000 modems

by Scott@TargetTestPrep » Sun Mar 15, 2020 4:21 am
BTGModeratorVI wrote: ↑
Fri Mar 06, 2020 5:56 pm
 A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

(A) d/800
(B) 5d/1000
(C) 125d
(D) d/1000 + 25
(E) 125/(1000d)

Answer: A
Source: Veritas Prep
The selling price for each modem is:

d/1000 * 5/4 = 5d/4000 = d/800

Answer: A

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