BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

A computer store originally bought 1,000 modems

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 1223
Joined: Sat Feb 15, 2020 2:23 pmFollowed by: 1 member
by BTGModeratorVI » Fri Mar 06, 2020 5:56 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

(A) d/800
(B) 5d/1000
(C) 125d
(D) d/1000 + 25
(E) 125/(1000d)

Answer: A
Source: Veritas Prep
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 2560
Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

Re: A computer store originally bought 1,000 modems

by swerve » Sat Mar 07, 2020 6:08 am
BTGModeratorVI wrote: ↑
Fri Mar 06, 2020 5:56 pm
 A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

(A) d/800
(B) 5d/1000
(C) 125d
(D) d/1000 + 25
(E) 125/(1000d)

Answer: A
Source: Veritas Prep
\begin{array}{|c|c|c|}
\hline
\text{Quantity} & \text{Each Cost} & Total \\ \hline
1000 & \dfrac{d}{1000} & d \\ \hline
\end{array}

Adding \(25\% \) to \(\dfrac{d}{1000} \quad \Rightarrow \quad \dfrac{d}{1000}\cdot \dfrac{125}{100} = \dfrac{d}{800}.\)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

Re: A computer store originally bought 1,000 modems

by Brent@GMATPrepNow » Sat Mar 07, 2020 7:12 am
BTGModeratorVI wrote: ↑
Fri Mar 06, 2020 5:56 pm
 A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

(A) d/800
(B) 5d/1000
(C) 125d
(D) d/1000 + 25
(E) 125/(1000d)

Answer: A
Source: Veritas Prep
Given: d = total cost of 1000 modems
So, d/1000 = cost of ONE modem

After the 25% increase, the retail price per modem = (d/1000) + 25% of (d/1000)
= (d/1000) + 0.25 (d/1000)
= d/1000 + 0.25d/1000
= 1.25d/1000
Check answer choices . . . . not there!
We need to find an equivalent form of 1.25d/1000 that's among the answer choices.

Take: 1.25d/1000
Divide top and bottom by 1.25 to get: d/800

Answer: A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8177
Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members
Location: Los Angeles, CA
Thanked: 43 times

Re: A computer store originally bought 1,000 modems

by Scott@TargetTestPrep » Sun Mar 15, 2020 4:21 am
BTGModeratorVI wrote: ↑
Fri Mar 06, 2020 5:56 pm
 A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

(A) d/800
(B) 5d/1000
(C) 125d
(D) d/1000 + 25
(E) 125/(1000d)

Answer: A
Source: Veritas Prep
The selling price for each modem is:

d/1000 * 5/4 = 5d/4000 = d/800

Answer: A

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1