AAPL wrote: ↑

Mon Jan 13, 2020 11:35 am

Veritas Prep

A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

A. \(\frac{d}{800}\)
B. \(\frac{5d}{1000}\)
C. \(125d\)
D. \(\frac{d}{1000}+25\)
E. \(\frac{125}{1000d}\)

OA A

The selling price for each modem is:

d/1000 * 5/4 = 5d/4000 = d/800

Answer: A

AAPL wrote: ↑

Mon Jan 13, 2020 11:35 am

Veritas Prep

A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

A. \(\frac{d}{800}\)
B. \(\frac{5d}{1000}\)
C. \(125d\)
D. \(\frac{d}{1000}+25\)
E. \(\frac{125}{1000d}\)

OA A

Given: d = total cost of 1000 modems
So, d/1000 = cost of ONE modem

After the 25% increase, the retail price per modem = (d/1000) + 25% of (d/1000)
= (d/1000) + 0.25 (d/1000)
= d/1000 + 0.25d/1000
= 1.25d/1000
Check answer choices . . . . not there!
We need to find an equivalent form of 1.25d/1000 that's among the answer choices.

Take: 1.25d/1000
Divide top and bottom by 1.25 to get: d/800

Answer: A

Cheers,
Brent