A computer routine was developed to generate two numbers,

BTGmoderatorDC wrote:A computer routine was developed to generate two numbers, ( x,y), the first being a random number between 0 and 100 inclusive, and the second being less than or equal to the square root of the first. Each of the following pairs satisfies this routine EXCEPT:

(A) (99, 10)
(B) (85, 9)
(C) (50, 7)
(D) (1 , 1)
(E) (1, 0)

OA A

Source: Official Guide

Say the first number is x; thus, the second one ≤ √x. With this in mind, let's look at the options.

(A) (99, 10): Here, x = 99. Thus, √x = √99 = 9... (not 10). But, the second number = 10 > 9.... not less than equal to 10. Correct answer. Though we got the answer, let's see other options too for the sake of understanding.
(B) (85, 9): Here, x = 85. Thus, √x = √85 = 9... (greater than 10). Thus, the second number = 9 ≤ 9....
(C) (50, 7): Here, x = 50. Thus, √x = √50 = 7... (greater than 7). Thus, the second number = 7 ≤ 7....
(D) (1 , 1): Here, x = 1. Thus, √x = √1 = 1. Thus, the second number = 1 ≤ 1
(E) (1, 0): Here, x = 1. Thus, √x = √1 = 1. Thus, the second number = 0 ≤ 1

The correct answer: A

Hope this helps!

-Jay
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BTGmoderatorDC wrote:A computer routine was developed to generate two numbers, ( x,y), the first being a random number between 0 and 100 inclusive, and the second being less than or equal to the square root of the first. Each of the following pairs satisfies this routine EXCEPT:

(A) (99, 10)
(B) (85, 9)
(C) (50, 7)
(D) (1 , 1)
(E) (1, 0)

OA A

Source: Official Guide

(A) (99, 10)
√100 = 10
So, √99 is LESS THAN 10
In other words, 10 is GREATER THAN √99
So, answer choice A breaks the rule that says the second number must be less than or equal to the square root of the first"

Answer: A

Cheers,
Brent

BTGmoderatorDC wrote:A computer routine was developed to generate two numbers, ( x,y), the first being a random number between 0 and 100 inclusive, and the second being less than or equal to the square root of the first. Each of the following pairs satisfies this routine EXCEPT:

(A) (99, 10)
(B) (85, 9)
(C) (50, 7)
(D) (1 , 1)
(E) (1, 0)

OA A

Source: Official Guide

Looking at the answer choices, we see that since √100 = 10, the square root of 99 is less than 10, so (99,10) cannot be the pair of numbers chosen.

Answer: A