A committee is to be created from some employees at Bongo

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VJesus12: Legendary Member; Posts: 2276; Joined: Sat Oct 14, 2017 6:10 amFollowed by: 3 members

by VJesus12 » Sun Apr 28, 2019 9:47 am

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A committee is to be created from some employees at Bongo Industrials. The committee must include exactly 3 senior executives and 4 junior executives. If 5 senior executives and 6 junior executives are available for the committee, how many different committees are possible?

1. 10
2. 15
3. 25
4. 60
5. 150

[spoiler]OA=E[/spoiler]

Source: Princeton Review

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Source: Beat The GMAT — Problem Solving | Sun Apr 28, 2019 9:47 am

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Jay@ManhattanReview: GMAT Instructor; Posts: 3008; Joined: Mon Aug 22, 2016 6:19 amFollowed by: 34 members; Location: Grand Central / New York; Thanked: 470 times

by Jay@ManhattanReview » Mon Apr 29, 2019 12:36 am

VJesus12 wrote:A committee is to be created from some employees at Bongo Industrials. The committee must include exactly 3 senior executives and 4 junior executives. If 5 senior executives and 6 junior executives are available for the committee, how many different committees are possible?

1. 10
2. 15
3. 25
4. 60
5. 150

[spoiler]OA=E[/spoiler]

Source: Princeton Review

Number of different committees are possible = 5C3 * 6C4 = 5C2 * 6C2 = (5.4/1.2) *(6.5/1.2) = 150

The correct answer: E

Hope this helps!

-Jay
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Scott@TargetTestPrep: GMAT Instructor; Posts: 8178; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Wed May 01, 2019 4:13 pm

VJesus12 wrote:A committee is to be created from some employees at Bongo Industrials. The committee must include exactly 3 senior executives and 4 junior executives. If 5 senior executives and 6 junior executives are available for the committee, how many different committees are possible?

1. 10
2. 15
3. 25
4. 60
5. 150

[spoiler]OA=E[/spoiler]

Source: Princeton Review

he number of possible committees is:

5C3 x 6C4

= (5 x 4 x 3)/3! x (6 x 5 x 4 x 3)/4!

= (5 x 4 x 3)/(3 x 2) x (6 x 5 x 4 x 3)/(4 x 3 x 2)

= 5 x 2 x 5 x 3 = 150

Answer: 5/E

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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