A circle is inscribed within a regular hexagon in such a way that the circle touches all sides of the hexagon at exactly one point per side. Another circle is drawn to connect all the vertices of the hexagon. Expressed as a fraction, what is the ratio of the area of the smaller circle to the area of the larger circle?
$$A.\ \sqrt{\frac{2}{3}}$$
$$B.\ \frac{\sqrt{2}}{3}$$
$$C.\ \frac{\sqrt{3}}{2}$$
$$D.\ \frac{\sqrt{3}}{4}$$
$$E.\ \frac{3}{4}$$
The OA is E.
I don't have clear this PS question. I appreciate if any expert explains it to me. Thank you so much.
$$A.\ \sqrt{\frac{2}{3}}$$
$$B.\ \frac{\sqrt{2}}{3}$$
$$C.\ \frac{\sqrt{3}}{2}$$
$$D.\ \frac{\sqrt{3}}{4}$$
$$E.\ \frac{3}{4}$$
The OA is E.
I don't have clear this PS question. I appreciate if any expert explains it to me. Thank you so much.
