A chemical supply company has 60 liters of a 40% HNO3 solution. How many liters of pure undiluted HNO3 must the chemist add so that the resultant solution is a 50% solution?
A. 12
B. 15
C. 20
D. 24
E. 30
The OA is A.
I get the solution in the following way,
60 liters of a 40% HNO3 solution means HNO3 = 24 liters in 60 liters of the solution.
Now, let x be the pure HNO3 added.
As per question,
24 + x = 50% of (60 + x)
or x = 12. Option A.
Experts, any suggestion about it? Thanks in advance.
A. 12
B. 15
C. 20
D. 24
E. 30
The OA is A.
I get the solution in the following way,
60 liters of a 40% HNO3 solution means HNO3 = 24 liters in 60 liters of the solution.
Now, let x be the pure HNO3 added.
As per question,
24 + x = 50% of (60 + x)
or x = 12. Option A.
Experts, any suggestion about it? Thanks in advance.
