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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## A certain scholarship committee awarded scholarships in the tagged by: BTGmoderatorLU ##### This topic has 3 expert replies and 1 member reply ### Top Member ## A certain scholarship committee awarded scholarships in the ## Timer 00:00 ## Your Answer A B C D E ## Global Stats Difficult Source: GMAT Prep A certain scholarship committee awarded scholarships in the amounts of$1250, $2500 and$4000. The Committee awarded twice as many $2500 scholarships as$4000 and it awarded three times as many $1250 scholarships as$2500 scholarships. If the total of $37500 was awarded in$1250 scholarships, how many $4000 scholarships were awarded? A. 5 B. 6 C. 9 D. 10 E. 15 The OA is A. ### GMAT/MBA Expert GMAT Instructor Joined 09 Oct 2010 Posted: 707 messages Followed by: 26 members Upvotes: 59 BTGmoderatorLU wrote: Source: GMAT Prep A certain scholarship committee awarded scholarships in the amounts of$1250, $2500 and$4000. The Committee awarded twice as many $2500 scholarships as$4000 and it awarded three times as many $1250 scholarships as$2500 scholarships. If the total of $37500 was awarded in$1250 scholarships, how many $4000 scholarships were awarded? A. 5 B. 6 C. 9 D. 10 E. 15 $$\left. \matrix{ A\,\,:\,\,\,\ 125 \cdot 10\,\, \hfill \cr B:\,\,\,\ 250 \cdot 10 \hfill \cr C:\,\,\,\ 400 \cdot 10\, \hfill \cr} \right\}\,\,\,{\rm{each}}$$ $$A:B:C = 6:2:1\,\,\,\left( {{\rm{quantities}}} \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\left\{ \matrix{ A = 6k \hfill \cr B = 2k \hfill \cr C = k \hfill \cr} \right.\,\,\,\,\,\,\,\left( {k \ge 1\,\,{\mathop{\rm int}} } \right)$$ $$6k\,\,\,A\,\,{\rm{units}}\,\, \cdot \,\,\left( {{{\ 125 \cdot 10} \over {1\,\,A\,\,{\rm{unit}}}}\,\,\matrix{ \nearrow \cr \nearrow \cr } } \right)\,\,\,\,\,\, = \,\,\,\,\,\ \,3750 \cdot 10\,\,\,\,$$ Obs.: arrows indicate licit converter (UNITS CONTROL technique). $$? = k = \frac{{3750}}{{6 \cdot 125}} = \underleftrightarrow {\frac{{3750}}{{3 \cdot 250}} = \frac{{375}}{{3 \cdot 25}}} = \frac{{125}}{{25}} = 5$$ This solution follows the notations and rationale taught in the GMATH method. Regards, Fabio. _________________ Fabio Skilnik :: www.GMATH.net (Math for the GMAT) Course release PROMO : finish our test drive till 31/Oct with (at least) 60 correct answers out of 92 (12-questions Mock included) to gain a 60% discount! ### Top Member Legendary Member Joined 02 Mar 2018 Posted: 597 messages Followed by: 1 members There are 3 types of scholarships. Let$1250 scholarships = A
Let $2500 scholarships = B Let$4000 scholarships =C
There are twice as many $250 scholarships as$4000 scholarships. This is a ratio that can be written as B : C = 2 : 1
The number of $1250 scholarships is three time the number of$2500 scholarships. This is also certain and it can be written as A : B = 3 : 1 by combining ratio A : B and B : C we will get A : B : C = 6 : 2 : 1

Now $37500 is the total amount of$1250 scholarships and B is twice as many of C.
$$Hence,\ \frac{37500}{1250}=30\ scholarships$$
Number of A is three times the number of B
$$Hence,\ \frac{30}{3}\ =10\ scholarships\ for\ 2500$$
$$Hence,\ \frac{10}{2}\ =5\ scholarships\ for\ 4000$$

Option A is CORRECT.

### GMAT/MBA Expert

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Hi All,

We're told that a certain scholarship committee awarded scholarships in the amounts of $1250,$2500 and $4000 - there are twice as many$2500 scholarships as $4000 and it awarded three times as many$1250 scholarships as $2500 scholarships. A total of$37500 was awarded in $1250 scholarships. We're asked for the number of$4000 scholarships that were awarded.

To start, I'm going to assign a variable to each type

A = the number of $1250 scholarships B = the number of$2500 scholarships
C = the number of $4000 scholarships From the prompt, we're told that there were twice as many$2500 scholarships as $4000 scholarships. This ratio can be written asâ€¦ B:C 2:1 We're also told that the number of$1250 scholarships is three times the number of $2500 scholarships. This ratio can be written asâ€¦ A:B 3:1 So, we haveâ€¦ A:B 3:1 ...B:C ...2:1 Combining ratios, we getâ€¦ A:B:C 6:2:1 This means that the number of$1250 scholarships is some multiple of 6 and the number of $2500 scholarships is an equivalent multiple of 2. We're told that the number of$1250 scholarships totaled $37,500â€¦. 37,500/1250 = 30 There were thirty$1250 scholarships awarded. Using the final ratio, we can deduce that there were ten $2500 scholarships and five$4000 scholarships.

Final Asnwer: A

GMAT assassins aren't born, they're made,
Rich

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BTGmoderatorLU wrote:
Source: GMAT Prep

A certain scholarship committee awarded scholarships in the amounts of $1250,$2500 and $4000. The Committee awarded twice as many$2500 scholarships as $4000 and it awarded three times as many$1250 scholarships as $2500 scholarships. If the total of$37500 was awarded in $1250 scholarships, how many$4000 scholarships were awarded?

A. 5
B. 6
C. 9
D. 10
E. 15
We can let a = the number of $1250 scholarships, b = the number of$2500 scholarships, and c = he number of $4000 scholarships. Since the committee awarded twice as many$2500 scholarships as $4000 scholarships: b = 2c Since it awarded three times as many$1250 scholarships as $2500 scholarships: a = 3b Since b = 2c, we see that a = 3(2c) = 6c. Since a total of$37500 was awarded in $1250 scholarships: 1250a = 37,500 a = 30 Since a = 6c, we see that c = a/6 = 30/6 = 5. Answer: A _________________ Scott Woodbury-Stewart Founder and CEO • 5-Day Free Trial 5-day free, full-access trial TTP Quant Available with Beat the GMAT members only code • Free Veritas GMAT Class Experience Lesson 1 Live Free Available with Beat the GMAT members only code • Award-winning private GMAT tutoring Register now and save up to$200

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