baalok88 wrote:
A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. What is the total fine for a book on the fourth day it is overdue?
(A) $0.60
(B) $0.70
(C) $0.80
(D) $0.90
(E) $1.00
We need to determine the total amount of a fine for a book that is 4 days overdue. Let’s determine each fine levied for when the book is overdue 1, 2, 3, or 4 days.
1 day overdue: $0.10
2 days overdue: The lesser of ($0.10 + $0.30 = $0.40) or (2 x $0.10 = $0.20)
Thus, the total fine for a book that is 2 days overdue is $0.20.
3 days overdue: The lesser of ($0.20 + $0.30 = $0.50) or (2 x $0.20 = $0.40)
Thus, the total fine for a book that is 3 days overdue is $0.40.
4 days overdue: The lesser of ($0.40 + $0.30 = $0.70) and (2 x $0.40 = $0.80)
Thus, the total fine for a book that is 4 days overdue is $0.70.
Note that the problem says the “total fine” is either increased by $0.30 or doubled. That’s why, for each day’s second calculation, we didn’t need to add the previous day’s fine. If you don’t read carefully, you might end up doubling the fine and adding it to the previous day’s fine.
Answer:
B
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