swerve wrote: ↑

Mon Feb 03, 2020 3:42 pm

A certain kennel will house 24 dogs for 7 days. Each dog requires 10 ounces of dog food per day. If the kennel purchases dog food in cases of 30 cans each and if each can holds 8 ounces of dog food, how many cases will the kennel need to feed all of the dogs for 7 days?

A. 5
B. 6
C. 7
D. 8
E. 9

The OA is C

Source: GMAT Prep

Amount of dog food required for 24 dogs for 7 days = 10*24*7 ounces;
Amount of dog food in each case = 30*8 ounces

Number of cases required = 10*24*7/30*8 = 7 cases

The correct answer: C

Hope this helps!

-Jay
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swerve wrote: ↑

Mon Feb 03, 2020 3:42 pm

A certain kennel will house 24 dogs for 7 days. Each dog requires 10 ounces of dog food per day. If the kennel purchases dog food in cases of 30 cans each and if each can holds 8 ounces of dog food, how many cases will the kennel need to feed all of the dogs for 7 days?

A. 5
B. 6
C. 7
D. 8
E. 9

The OA is C

Source: GMAT Prep

Since each dog requires 10 ounces of dog food per day, 24 dogs require 10 x 24 = 240 ounces of dog food per day and 240 x 7 = 1680 ounces of dog food for the 7 days.

Since each case of dog food has 30 cans and each can has 8 ounces of dog food, a case has 30 x 8 = 240 ounces of dog food.

Therefore, 1680/240 = 7 cases of dog food are needed to feed 24 dogs for 7 days.

Answer: C