melguy wrote:A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase?
(A) 10
(B) 11
(C) 12
(D) 13
(E) 14
Let $B = the amount spent on bananas and $A = the amount spent on apples.
Since each banana sells for 50 cents, we get the following options for $B, in cents:
50, 100, 150, 200...
Every value in the list above ends in 50 or 00.
Implication:
Since $B + $A = 630, $A must end in either 80 or 30.
Since each apple sells for 70 cents, we get the following options for $A:
70, 140, 210,
280...
Test the value in blue.
If $A = 280, then $B = 630-280 = 350.
In this case:
Number of apples purchased = (total spent on apples)/(price per apple) = 280/70 = 4.
Number of bananas purchased = (total spent on bananas)/(price per banana) = 350/50 = 7.
Total amount of fruit purchased = 4+7 = 11.
The correct answer is
B.
Last edited by GMATGuruNY on Sat Dec 17, 2016 9:04 pm, edited 1 time in total.
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