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A certain boxer has agreed to pay his opponent a fee of 2.5%

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by BTGmoderatorLU » Thu Oct 03, 2019 7:52 am
Source: Veritas Prep

A certain boxer has agreed to pay his opponent a fee of 2.5% of his total purse for every pound over the specified weight limit he weighs in. If the boxer pays his opponent a fee of $26,250 after weighing in seven pounds over the specified limit, what was the boxer's purse?

A. $65,625
B. $105,000
C. $150,000
D. $183,750
E. $1,050,000

The OA is C
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by swerve » Fri Oct 04, 2019 3:50 am
BTGmoderatorLU wrote:Source: Veritas Prep

A certain boxer has agreed to pay his opponent a fee of 2.5% of his total purse for every pound over the specified weight limit he weighs in. If the boxer pays his opponent a fee of $26,250 after weighing in seven pounds over the specified limit, what was the boxer's purse?

A. $65,625
B. $105,000
C. $150,000
D. $183,750
E. $1,050,000

The OA is C
We can try as follows:

2.5% of his total purse for every pound over the specified weight limit.

His opponent weighs seven pounds over the specified limit.

\(7 \cdot x \cdot \frac{2.5}{100} = 26250\)

Solve for \(x\).

\(x = 150,000\)
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