A certain aquarium feeds its penguins a total of 80 pounds of fish each day. If the aquarium had 6 fewer penguins, and the remaining penguins were fed their usual portions, the aquarium would feed its penguins a total of 15 pounds less fish each day. If each of the penguins receives the same amount of fish each day, how many penguins does the aquarium have? A 32 Correct Answer B 38 C 45 D 74 E 80 a?

Let there be a total of X penguins Now, X penguins are feeded -> 80 pounds of fish each day 1 penguin -> 80/X 6 penguins -> 80/X *6 Since each of the penguins receives the same amount of fish each day,therefore 80/X *6=15 (Because 6 fewer penguins reduced the feed by 15 pounds each day) therefore, X=32 Option A

varun289 wrote:A certain aquarium feeds its penguins a total of 80 pounds of fish each day. If the aquarium had 6 fewer penguins, and the remaining penguins were fed their usual portions, the aquarium would feed its penguins a total of 15 pounds less fish each day. If each of the penguins receives the same amount of fish each day, how many penguins does the aquarium have? A 32 B 38 C 45 D 74 E 80 6 fewer penguins = 15 fewer pounds of fish, implying the following proportion: (6 penguins)/(15 pounds of fish) = (x penguins)/(80 pounds of fish) 2/5 = x/80 5x = 160 x = 32. The correct answer is A.

since dite of each pangune is same let x number of P 80/x = 65/(x-6) x= 32

6 penguins = 15 pounds x = No. of pounds per penguin x = 15/6 WKT, 80/x = Total penguins = > 80/(15/6) => 32

x penguins are fed 80 pounds/day. So 1 penguin will be fed 80/x if (x-6) penguins were to be fed the same amount then (x-6)*80/x which happens to be 65 so the equation (x-6)*80/x = 65 80x-480 = 65x 15x=480 x=32 ... Answer A