A caterer must choose 3 canapes to serve from 12 possible selections. In how many possible combinations can he serve the

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BTGmoderatorDC: Moderator; Posts: 7187; Joined: Thu Sep 07, 2017 4:43 pmFollowed by: 23 members

by BTGmoderatorDC » Mon Aug 24, 2020 6:21 pm

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A caterer must choose 3 canapés to serve from 12 possible selections. In how many possible combinations can he serve the 3 canapés?

A. 220
B. 440
C. 660
D. 1,100
E. 1,320

OA A

Source: Princeton Review

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Source: Beat The GMAT — Problem Solving | Mon Aug 24, 2020 6:21 pm

sjain296: Junior | Next Rank: 30 Posts; Posts: 23; Joined: Fri Jun 28, 2019 9:57 pm

Re: A caterer must choose 3 canapes to serve from 12 possible selections. In how many possible combinations can he serve

by sjain296 » Mon Aug 24, 2020 11:08 pm

3 things have to be selected from 12 possible options

No of ways to do that = 12 C 3 = 220

Option A

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swerve: Legendary Member; Posts: 2560; Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

Re: A caterer must choose 3 canapes to serve from 12 possible selections. In how many possible combinations can he serve

by swerve » Tue Aug 25, 2020 12:45 pm

BTGmoderatorDC wrote: ↑
Mon Aug 24, 2020 6:21 pm
A caterer must choose 3 canapés to serve from 12 possible selections. In how many possible combinations can he serve the 3 canapés?

A. 220
B. 440
C. 660
D. 1,100
E. 1,320

OA A

Source: Princeton Review

Total ways of serving $3$ canapes from a possible $12$ combinations can be given by $12c3$

$12c3 = \dfrac{12∗11∗10}{3∗2} = 220 \Longrightarrow$A

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8176; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

Re: A caterer must choose 3 canapes to serve from 12 possible selections. In how many possible combinations can he serve

by Scott@TargetTestPrep » Sat Sep 05, 2020 12:17 pm

BTGmoderatorDC wrote: ↑
Mon Aug 24, 2020 6:21 pm
A caterer must choose 3 canapés to serve from 12 possible selections. In how many possible combinations can he serve the 3 canapés?

A. 220
B. 440
C. 660
D. 1,100
E. 1,320

OA A

Solution:

The number of possible ways in which he can serve the 3 canapés from 12 is:

12C3 = (12 x 11 x 10)/(3 x 2) = 4 x 11 x 5 = 220

Answer: A

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