A box contains one dozen donuts. Four of the donuts are

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BTGmoderatorLU: Moderator; Posts: 2558; Joined: Sun Oct 15, 2017 1:50 pmFollowed by: 6 members

by BTGmoderatorLU » Thu Aug 22, 2019 10:43 am

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Source: Manhattan Prep

A box contains one dozen donuts. Four of the donuts are chocolate, four are glazed, and four are jelly. If two donuts are randomly selected from the box, one after the other, what is the probability that both will be jelly donuts?

A.1/11
B. 1/9
C. 1/3
D. 2/3
E. 8/9

The OA is A

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Source: Beat The GMAT — Problem Solving | Thu Aug 22, 2019 10:43 am

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Brent@GMATPrepNow: GMAT Instructor; Posts: 16207; Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members; Location: Vancouver, BC; Thanked: 5254 times; GMAT Score:770

by Brent@GMATPrepNow » Thu Aug 22, 2019 12:43 pm

BTGmoderatorLU wrote:Source: Manhattan Prep

A box contains one dozen donuts. Four of the donuts are chocolate, four are glazed, and four are jelly. If two donuts are randomly selected from the box, one after the other, what is the probability that both will be jelly donuts?

A.1/11
B. 1/9
C. 1/3
D. 2/3
E. 8/9

The OA is A

P(both are jelly) = P(1st selection is jelly AND 2nd selection is jelly)
= P(1st selection is jelly) x P(2nd selection is jelly)
= 4/12 x 3/11
= 1/11

Answer: A

Cheers,
Brent

Brent Hanneson - Creator of GMATPrepNow.com

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swerve: Legendary Member; Posts: 2548; Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

by swerve » Thu Aug 22, 2019 2:41 pm

BTGmoderatorLU wrote:Source: Manhattan Prep

A box contains one dozen donuts. Four of the donuts are chocolate, four are glazed, and four are jelly. If two donuts are randomly selected from the box, one after the other, what is the probability that both will be jelly donuts?

A.1/11
B. 1/9
C. 1/3
D. 2/3
E. 8/9

The OA is A

Probability of getting the first Jelly doughnut - $\frac{4}{12}$

Probability of getting the second Jelly doughnut - $\frac{3}{11}$

Total probability $= \frac{4}{12} \cdot \frac{3}{11} = \frac{1}{11}$

Therefore, the correct option is __A__

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8156; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Sat Aug 24, 2019 4:19 am

BTGmoderatorLU wrote:Source: Manhattan Prep

A box contains one dozen donuts. Four of the donuts are chocolate, four are glazed, and four are jelly. If two donuts are randomly selected from the box, one after the other, what is the probability that both will be jelly donuts?

A.1/11
B. 1/9
C. 1/3
D. 2/3
E. 8/9

The OA is A

The probability of selecting two jelly donuts is:

4/12 x 3/11 = 1/3 x 3/11 = 1/11

Answer: A

Scott Woodbury-Stewart
Founder and CEO
[email protected]

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

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