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A basket contains 5 apples, of which 1 is spoiled and the

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by AAPL » Fri Sep 06, 2019 1:44 am
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A basket contains 5 apples, of which 1 is spoiled and the rest are good. If Herny is to select 2 apples from the basket simultaneously and at random, what is the probability that the 2 apples selected will include the spoiled apple?

A. 1/5
B. 3/10
C. 2/5
D. 1/2
E. 3/5

OA C
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Source: — Problem Solving |

by Brent@GMATPrepNow » Fri Sep 06, 2019 4:31 am
AAPL wrote:GMAT Prep

A basket contains 5 apples, of which 1 is spoiled and the rest are good. If Herny is to select 2 apples from the basket simultaneously and at random, what is the probability that the 2 apples selected will include the spoiled apple?

A. 1/5
B. 3/10
C. 2/5
D. 1/2
E. 3/5
OA C
P(1 of the selected apples is spoiled) = P(1st selection is spoiled AND 2nd selection is fine OR 1st selection is fine AND 2nd selection is spoiled)
= P(1st selection is spoiled AND 2nd selection is fine) + P(1st selection is fine AND 2nd selection is spoiled)
= P(1st selection is spoiled) x P(2nd selection is fine) + P(1st selection is fine) x P(2nd selection is spoiled)
= [1/5 x 4/4] + [4/5 x 1/4]
= 1/5 + 1/5
= 2/5

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Brent@GMATPrepNow » Fri Sep 06, 2019 4:32 am
AAPL wrote:GMAT Prep

A basket contains 5 apples, of which 1 is spoiled and the rest are good. If Herny is to select 2 apples from the basket simultaneously and at random, what is the probability that the 2 apples selected will include the spoiled apple?

A. 1/5
B. 3/10
C. 2/5
D. 1/2
E. 3/5

OA C
Since there are so few objects involved (5 apples), we should be able to quickly answer the question by simply listing and counting

Let A, B, C, D, and E represent the 5 apples, and let E represent the SPOILED APPLE

We want to select 2 apples at random. So, let's list all of the possible outcomes:
1) AB
2) AC
3) AD
4) AE
5) BC
6) BD
7) BE
8) CD
9) CE
10) DE

So, there are 10 possible outcomes
Of those 10 possible outcomes, 4 outcomes include the SPOILED APPLE

So, P(selection includes the spoiled apple) = 4/10 = 2/5

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Scott@TargetTestPrep » Mon Sep 09, 2019 6:26 pm
AAPL wrote:GMAT Prep

A basket contains 5 apples, of which 1 is spoiled and the rest are good. If Herny is to select 2 apples from the basket simultaneously and at random, what is the probability that the 2 apples selected will include the spoiled apple?

A. 1/5
B. 3/10
C. 2/5
D. 1/2
E. 3/5

OA C
We need to determine the probability of selecting a spoiled apple and a non-spoiled apple when selecting two apples.

The number of ways to select the spoiled apple is 1C1 = 1. The number of ways to select one good apple is 4C1 = 4. Thus, the spoiled apple and a good apple can be selected in 1 x 4 = 4 ways.

The number of ways to select 2 apples from 5 is 5C2 = (5 x 4)/2! = 20/2 = 10.

Thus, the probability of selecting the spoiled apple and a good apple is 4/10 = 2/5.

Alternate Solution:

There are two outcomes that satisfy the requirement that the spoiled apple (S) is chosen along with a good apple (G), either S-G or G-S. The probability of S-G is (1/5)(4/4) = 1/5. The probability of G-S is (4/5)(1/4) = 1/5. Since either outcome satisfies our requirement, we add these two probabilities: 1/5 + 1/5 = 2/5.

Answer: C

Scott Woodbury-Stewart
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