A bag contains $x$ blue chips and $y$ red chips. If the probability of selecting a red chip at random is

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Vincen: Legendary Member; Posts: 2898; Joined: Thu Sep 07, 2017 2:49 pmFollowed by: 5 members; Thanked: 6 times

by Vincen » Sat May 30, 2020 1:54 pm

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A bag contains $x$ blue chips and $y$ red chips. If the probability of selecting a red chip at random is $\dfrac37,$ then $\dfrac{x}{y} =$

A. $\dfrac7{11}$
B. $\dfrac34$
C. $\dfrac74$
D. $\dfrac43$
E. $\dfrac{11}7$

[spoiler]OA=D[/spoiler]

Source: Magoosh

Source: Beat The GMAT — Problem Solving | Sat May 30, 2020 1:54 pm

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Re: A bag contains $x$ blue chips and $y$ red chips. If the probability of selecting a red chip at random is

by Brent@GMATPrepNow » Tue Jun 02, 2020 5:42 am

Vincen wrote: ↑
Sat May 30, 2020 1:54 pm
A bag contains $x$ blue chips and $y$ red chips. If the probability of selecting a red chip at random is $\dfrac37,$ then $\dfrac{x}{y} =$

A. $\dfrac7{11}$
B. $\dfrac34$
C. $\dfrac74$
D. $\dfrac43$
E. $\dfrac{11}7$

[spoiler]OA=D[/spoiler]

Source: Magoosh

We can quickly solve this question by testing values that satisfy the given information

GIVEN: The probability of selecting a red chip at random is 3/7
So, it COULD be the case that there are 3 red chips, and a TOTAL of 7 chips
If there are 7 chips and 3 are red, then the other 4 chips must be blue
In other words, y = 3 and x = 4

This means x/y = 4/3

Answer: D

Cheers,
Brent

Brent Hanneson - Creator of GMATPrepNow.com

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