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A baffling problem

Expert replies
Source: — Data Sufficiency |

by thephoenix » Sun Apr 11, 2010 11:05 am
IS the ans D
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by papumba2011 » Sun Apr 11, 2010 11:32 am
thephoenix wrote:IS the ans D
Yes. Can you explain the answer a bit. I actually want to know the process by which you aarrive at the value using stmt 1.
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by neoreaves » Sun Apr 11, 2010 11:57 am
to simplify the first expression lets say z = x- 5

then sqrt(z^2) = -z

the LHS is definitely positive as we are squaring z and then taking a sqrt of it ....so in ths process if it is a negative number we will get a positive and if it is a positive number then we get the same positive number


so LHS serves as a modulus operator similar to |z| ...

however, notice that RHS is -z ....this indicates one thing and that is z < 0 ...thus a -z is a positive number ..

Thus from all this what we are getting at is z < 0 which in our case is x - 5 < 0 --> x < 5 ??

That is what we have to find out

1) x < 0 .........so our answer to x < 5 is here ....yes it is less than 5 !! ...so Sufficient

2) 5 -x > 0

5 > x
or x < 5 .....again answers our questions ...so Sufficient
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by dxgamez » Sun Apr 11, 2010 5:17 pm
@neoreaves

Can we also multiply the powers of (x-5) or z in your expression?

{(z)^2}^1/2 = z ?

Can we do this? Or rather when should we simplify the expression?
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by neoreaves » Sun Apr 11, 2010 9:11 pm
dxgamez wrote:@neoreaves

Can we also multiply the powers of (x-5) or z in your expression?

{(z)^2}^1/2 = z ?

Can we do this? Or rather when should we simplify the expression?

Yes we can do this. But I think that is not the point here .....GMAT inequalities are nothing like the inequalities you or I have encountered in real life ....we have to make sense of what the equality is saying ....so look at the broader picture ...even if you cancel out the powers you get z ...but the RHS is -z ...Why is this ??.....the only possibility is z < 0 .....so all this mumbo jumbo is created by GMAT so you can arrive at this conclusion ...that z < 0 .....try to read the inequality what is it saying .....simplifying an equality is not wrong ...but interpretting it is GOLD .....take a few numbers play with this inequality ....i know it took me quiet some time to get comfortable with this but I am sure you can do better than me
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by dxgamez » Sun Apr 11, 2010 10:27 pm
thanks for your valuable advise, neoreaves. appreciate it :D
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by harshavardhanc » Sun Apr 11, 2010 11:45 pm
papumba2011 wrote:Is{ (x-5)^(2)}^(1/2) = 5-x
1) -x|x| > 0
2) 5-x > 0
sqrt of ( (x-5)^2) can be

+(x-5) or -(x-5)

the question is asking if it is the second one.

The root will be -(x-5) when x-5 < 0 or X<5.

statement 1 : gives us x<0 . Sufficient.

statement 2 : directly gives us x<5. sufficient.

Hence , D.
Regards,
Harsha
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by gmatmachoman » Mon Apr 12, 2010 1:03 am
papumba2011 wrote:Is{ (x-5)^(2)}^(1/2) = 5-x
1) -x|x| > 0
2) 5-x > 0
Guys this is my way of reasoning. Plz do ch\k out if I am wrong !

It asks for whether (x-5) = (5-x)

St1 :
-x|x| > 0

In this case, x has to be negative number (x<0)

Plugging in some values of x (X<0) ,LHS is NOT equal to RHS.( Sufficient)

St 2: 5-x > 0---> x<5
Pluggng in values of X in the query we get LHS is NOT equal to RHS ( Sufficient)

IMO D.

Plz share ur view am i correct!!



st 2:
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