sanju09 wrote:A B
+ B
____
B A
____
In the correctly worked addition problem above, A and B represent digits. What is A?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Alternatively, we can apply some logic here.
We can make 2 conclusions:
1) When we add B+B the units digit of the sum is A
This means that A must be even. So, we can eliminate A, C and E.
2) When we add B+B, the sum is greater than 9.
We know this because we begin with a tens digit of A (as in AB) and once we add B, the sum becomes BA where the tens digit is now B.
Since we already know that the answer is B or D, we can just check each one.
This won't take long since we need only check
one of these answer choices. If B works, we're done. If B doesn't work, the answer
must be D.
Let's check answer choice B, which says A=6
If A = 6, then B must equal 8 (since 8+8=16)
If A=6 and B=8, we get: 68+8=86 (doesn't work, eliminate B)
So, the answer
must be
D
. . . Now, if we want to kill some time before the next question we
could check this answer choice, but I'd just move on to the next question.
Let's check answer choice D (for the timid

)
Answer choice D says A=8
If A = 8, then B must equal 9 (since 9+9=18)
If A=8 and B=9, we get: 89+9=98 (WORKS!)
So, the answer is
D
Cheers,
Brent