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A \(20\) kilograms mixture of dry fruits consisting of \(x\) percent of almonds is formed by mixing 'a' kilograms of mixture A and 'b' kilograms of mixture B. If mixture A consists of 'y' percent of almonds and mixture B consists of 20% of almonds, what is the weight of almonds in kilograms in mixture A? Assume that each mixture has a uniform composition, that is, samples taken from any part in a mixture will have the same composition as the overall mixture.
(1) The amount of almonds in mixture B is three-fifths of the total weight of mixture A
(2) If the weight of the final mixture is reduced by 25 percent, the almonds in the final mixture would reduce by 1.5 kilograms
Answer:C
Source:e-GMAT
(1) The amount of almonds in mixture B is three-fifths of the total weight of mixture A
(2) If the weight of the final mixture is reduced by 25 percent, the almonds in the final mixture would reduce by 1.5 kilograms
Answer:C
Source:e-GMAT
















