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50 children attended a carnival where cotton candy and ice cream were sold. If 14 children ate only cotton candy, 18 children ate only ice cream, and 8 children had neither cotton candy nor ice cream, how many children ate ice cream?
A. 18
B. 20
C. 24
D. 28
E. 32
The OA is D.
This is an approach to solving this question (Double Matrix Method),
1. 14 children only cotton candy, 18 only ice cream, and 8 children no cotton candy and ice cream.
2. Only one left category: both ate cotton candy and ice cream, which is 50 - 14 - 18 - 8 = 10.
3. Thus, children who ate ice cream = children ONLY ate ice cream + BOTH = 18 + 10 = 28.
Has anyone another strategic approach to solve this PS question? Regards!
A. 18
B. 20
C. 24
D. 28
E. 32
The OA is D.
This is an approach to solving this question (Double Matrix Method),
1. 14 children only cotton candy, 18 only ice cream, and 8 children no cotton candy and ice cream.
2. Only one left category: both ate cotton candy and ice cream, which is 50 - 14 - 18 - 8 = 10.
3. Thus, children who ate ice cream = children ONLY ate ice cream + BOTH = 18 + 10 = 28.
Has anyone another strategic approach to solve this PS question? Regards!
