Hi Kourousafama,
Can you please post one question per topic in the future?
Question 1
1/(5)^m x 1/(4)^18 = 1/(2x(10)^35)
Lets inverse everything first
5^m x 4^18 = 2 x (10)^35
=> 5^m x 2^36 = 2 x 2^35 x 5^35 (4 = 2^2 and 10 = 2x5)
=> 5^m x 2^36 = 2^36 x 5^35
=> m = 35
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5 PS answer explanation needed / GMATPrep Test 1
Source: Beat The GMAT — Problem Solving |
Question 2:
The key is to realise that ABC is a right triangle, with ABC = 90
Area = 1/2 x BC x AC
= 1/2 x 1 x 2 = 1
The key is to realise that ABC is a right triangle, with ABC = 90
Area = 1/2 x BC x AC
= 1/2 x 1 x 2 = 1
Question 3
Let selling price = x
Markup = 0.4x
We get the equation:
x = 150 + 0.4x => x = 250
Thus, SP = 250, CP = 150, thus profit = 250 - 150 = 100
Let selling price = x
Markup = 0.4x
We get the equation:
x = 150 + 0.4x => x = 250
Thus, SP = 250, CP = 150, thus profit = 250 - 150 = 100
Question 5
Let # history majors = x
Thus, #English majors = 2x
# Mathematics majors = (2/3)x
Ratio history : maths = x : 2/3x = 3:2
Let # history majors = x
Thus, #English majors = 2x
# Mathematics majors = (2/3)x
Ratio history : maths = x : 2/3x = 3:2
Question 4:
Time taken by 6 machines to finish the work = 12 days
Let time taken by 1 machine = T. Now, Rate = 1/ time, and rates are additive
6/T = 1/12 => T = 72 [ 1/T + 1/T + 1/T + 1/T + 1/T + 1/T = 1/12]
So each machine takes 72 days to finish the work on it own
Number of machines needed to finish the work in 8 days = 72/8 = 9
Thus, #extra machines needed = 9 - 6 = 3
Time taken by 6 machines to finish the work = 12 days
Let time taken by 1 machine = T. Now, Rate = 1/ time, and rates are additive
6/T = 1/12 => T = 72 [ 1/T + 1/T + 1/T + 1/T + 1/T + 1/T = 1/12]
So each machine takes 72 days to finish the work on it own
Number of machines needed to finish the work in 8 days = 72/8 = 9
Thus, #extra machines needed = 9 - 6 = 3
Hello Mittal,
can you please explain the following part:
=> 5^m x 2^36 = 2 x 2^35 x 5^35 (4 = 2^2 and 10 = 2x5)
this is what i am doing and I don't understand how you got to yours.
(1/5^m)(1/4^18) = ..... since 5 and 4 = 20, i am just subtracting 18 from 35. hence I got 17 which is wrong.
can you please explain the following part:
=> 5^m x 2^36 = 2 x 2^35 x 5^35 (4 = 2^2 and 10 = 2x5)
this is what i am doing and I don't understand how you got to yours.
(1/5^m)(1/4^18) = ..... since 5 and 4 = 20, i am just subtracting 18 from 35. hence I got 17 which is wrong.
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
- Alfred A. Montapert, Philosopher.
Hey,kmittal82 wrote:Question 3
Let selling price = x
Markup = 0.4x
We get the equation:
x = 150 + 0.4x => x = 250
Thus, SP = 250, CP = 150, thus profit = 250 - 150 = 100
Where did you get the 250 from?
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
- Alfred A. Montapert, Philosopher.
i have little doubt about right answer herekmittal82 wrote:Question 2:
The key is to realise that ABC is a right triangle, with ABC = 90
Area = 1/2 x BC x AC
= 1/2 x 1 x 2 = 1
i agree that triangle ABC right triangle with ABC=90
but to me the area =1/2*base(BC)*leg(AB)=1/2*1*(3^1/2)=(3^1/2)/2. it is not hypotenuse*base as in above solution
what i am missing here?
Let Know:Gurpinder wrote:Hello Mittal,
can you please explain the following part:
=> 5^m x 2^36 = 2 x 2^35 x 5^35 (4 = 2^2 and 10 = 2x5)
this is what i am doing and I don't understand how you got to yours.
(1/5^m)(1/4^18) = ..... since 5 and 4 = 20, i am just subtracting 18 from 35. hence I got 17 which is wrong.
5^m x 2^36 = 2 x 2^35 x 5^35 (4 = 2^2 and 10 = 2x5)[/b]
= 5^m x 2^36=2^1 x 2^35 x 5^35
=5^m x 2x36=2^36 x 5^35
so, m=35
x = 150 + 0.4xGurpinder wrote:Hey,kmittal82 wrote:Question 3
Let selling price = x
Markup = 0.4x
We get the equation:
x = 150 + 0.4x => x = 250
Thus, SP = 250, CP = 150, thus profit = 250 - 150 = 100
Where did you get the 250 from?
=> x - 0.4x = 150
=> 0.6x = 150
=> x = 150/0.6 = 250
Hope thats clear
Crap, thanks for the correction clock, you are right I multiplied the hypotenuse by mistake (Glad this is not the real test day!)clock60 wrote:i have little doubt about right answer herekmittal82 wrote:Question 2:
The key is to realise that ABC is a right triangle, with ABC = 90
Area = 1/2 x BC x AC
= 1/2 x 1 x 2 = 1
i agree that triangle ABC right triangle with ABC=90
but to me the area =1/2*base(BC)*leg(AB)=1/2*1*(3^1/2)=(3^1/2)/2. it is not hypotenuse*base as in above solution
what i am missing here?
Your answer is correct, I apologise for my mistake.


















