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5 consecutive positive integers

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by acorra » Sun Sep 28, 2008 1:49 am
If the sum of five consecutive positive integers is A, then the su of the next five consecutive integers in terms of A is:
a) A+1
b) A+5
c) A+25
d) 2A
e) 5A
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by 4meonly » Sun Sep 28, 2008 2:34 am
A = summ of
x +x+1 +x+2 +x+3 +x+4

next 5 consequtive integers are
x+5 + x+1+5 + x+2+5 ...... ad 5 to each
and you'll get the difference 25

A+25

C

OA?
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by Mani_mba » Sun Sep 28, 2008 2:36 am
IMO C

The last integer of the first set of 5 consecutive integers: (A/5)+2
(A/5 is the average of the first set and also the third integer of the first set. Hence A/5 + 2 is the fifth integer of the first set)

the nos in the second set are

A/5+3, A/5+4, ......, A/5+7

Hence the sum is A + 25.

What is the OA ?
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by acorra » Sun Sep 28, 2008 2:39 am
OA is C

thanks guys
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by stop@800 » Sun Sep 28, 2008 6:52 am
In second set, every number will be 5 greater than the corresponding number in set 1

so 5*5 = 25
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