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4 ^ (4 x) = 1600

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by sanju09 » Fri Mar 18, 2011 3:11 am
If 4 ^ (4 x) = 1600, then what is the value of {4^ (x - 1)} ^2?
(A) 40
(B) 20
(C) 10
(D) 5/2
(E) 5/4



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by Night reader » Fri Mar 18, 2011 4:45 am
4^4x=(4^4)*6.25 OR (4^4)^x=(4^4)*6.25, (4^4)^(x-1)=6.25,
{(4^2)^(x-1)}^2=6.25, (4^2)^(x-1)=Sqrt(6.25); 6.25*4/4=25/4, Sqrt(25/4)=5/2

{4^(x-1)}^2= (4^2)^(x-1) =5/2


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sanju09 wrote:If 4 ^ (4 x) = 1600, then what is the value of {4^ (x - 1)} ^2?
(A) 40
(B) 20
(C) 10
(D) 5/2
(E) 5/4



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