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by ern5231 » Sat May 15, 2010 7:01 am
2x = 3y-5 and y ≠ 3, then (x-2) / (y-3) =?

the answer to this is 3 / 2. How is this possible to get??
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by Gmat_War » Sat May 15, 2010 7:07 am
2x=3y-5
=> y=2x/3 +5/3
=>y-3=(2x+5)/3 -3=(2x-4)/3
=>y-3=2(x-2)/3
=>(x-2)/(y-3)=3/2
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by harshavardhanc » Sat May 15, 2010 7:14 am
ern5231 wrote:2x = 3y-5 and y ≠ 3, then (x-2) / (y-3) =?

the answer to this is 3 / 2. How is this possible to get??
2x = 3y - 5

subtract 4 frm both sides

2x-4=3y-5-4

2x-4=3y-9

2(x-4) = 3 (y-3)

(x-4)/(y-3) = 3/2
Regards,
Harsha
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